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The FET can’t get rid of that heat but will absorb it in its thermal mass instead, heating up a little. It won’t be able to deliver 1A or more continuously, however – it can only do that catasheet short pulses. Email Required, but never shown. Mahendra Gunawardena 1, 9 In fact, the datasheet for the MIC states: By using our site, you acknowledge that you have read and understand our Cookie PolicyPrivacy Policyand our Terms datxsheet Service.

On page 4, bottom right, there’s a graph showing the maximum safe operating area SOA of the device.

IRLML Datasheet PDF –

Unimportant 1 6. Without a gate resistor the only thing limiting the current is the gate driver’s output resistance, which is supposedly low, it would not be a good driver otherwise.

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MOSFETs like the ones in the MIC’s output stage can handle large current pulses for a short time by simply absorbing the heat generated by the pulse in their thermal mass. By clicking “Post Your Answer”, you acknowledge that you have read our updated terms of serviceprivacy policy and cookie policyand that your continued use of the website is subject to these policies. As long as that doesn’t cause it to get hotter than its maximum junction temperature, no harm will be done.

Sign up using Email and Password. It will survive a pulse of 7A at 20V just fine as long as it’s only 10 microseconds long.

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Home Questions Tags Users Unanswered. If the pulse is short enough, the FET will not heat up much and therefore survive just fine.

(PDF) IRLML2803 Datasheet download

That’s W dissipated in a SOT device. So if you just short its output to ground, it will die. I would place a 0 ohm resistor there for future experimentation. This current is limited by its internal output resistance since there doesn’t seem to be a limiting circuit according to the datasheet’s diagram of the dstasheet stage.

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IRLML2803 PDF Datasheet浏览和下载

The Apps Engineer likely will not have access to any Fab details. My thinking is this should lead to current peaks that easily exceed the driver’s 1A maximum peak current and damage the chip, but the evaluation board demonstrates that this is not the case, what am I missing? The poly most modern processes use poly gates has some resistance; different Fabs have their own secret sauces.

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Owing to the fact that this gate driver features adaptive dead-time and thus monitors the gate of the MOSFET to determine when it has fully turned off, a gate resistor prevents proper sensing of the actual gate. The chip specifies the “typical” LO output current as 1A, not an absolute maximum.

It’s not current that kills a FET, it’s overheating. The current might be internally limited. At t 0 any capacitor will act like a short circuit.